LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长...

LCS问题就是求两个字符串最长公共子串的问题。解法就是用一个矩阵来记录两个字符串中所有位置的两个字符之间的匹配情况，若是匹配则为1，否则为0。然后求出对角线最长的1序列，其对应的位置就是最长匹配子串的位置。 最长递增子序列LCS的实现C源码！-LCS problem for two strings is the longest common sub-string problem. Solution is to use a matrix to record the location of two strings of all the matches between the two characters in the situation, if the match is one, otherwise to 0. And one of the longest diagonal obtained sequence, the location of its corresponding sub-string match is the longest position. The longest increasing sub-sequence source C implementation of the LCS!

最长递增子序列LCS的实现C源码
Debug
lcs.c
LCS.dsp
LCS.dsw
lcs.h
LCS.ncb
LCS.opt
LCS.plg
lcsMain.c