用汇编语言实现人名排序问题,根据字母的顺序排列,先比较首字母,如果相同则比较之后的字母-using assembly language to achieve names scheduling problem, according to the alphabetical order, compare the first letters of the alphabet, If the same comparison is the after letters
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.000984s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.073484s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.001125s ]
SELECT * FROM `jrk_tagrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 20 [ RunTime:0.001338s ]
SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.001082s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.003163s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.001426s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003797s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.015188s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.001205s ]
UPDATE `jrk_articles` SET `hits` = 2 WHERE `id` = 135663 [ RunTime:0.030686s ]
