程序的要求是已知的，几个节点和节点的函数（×），…

本程序的要求是已知几个节点x及节点函数f（x），要求近似函数！只要输出每点函数，对角线上的值，和最后一行的值，为继续插值准备！ 例如：0.00 0.00000 0.20 0.20134 0.30 0.30452 0.50 0.52110 得到结果：0.00000 0.20134 1.006700 0.30452 0.083666 0.52110 1.082900 0.170333 0.173334 f(0.230000)=0.249337 Rx(0.230000)=-1.46917e-09f-the procedural requirements are known, several nodes and node x function f (x), requiring similar function! As long as output per function point, the value of a diagonal, and the last line of duty, prepared to continue interpolation! For example : 0.00 0.00000 0.20134 0.30 0.20 0.50 0.52110 0.30452 outcome : 0.00000 0.30452 0.20134 1.006700 1.082900 0.083666 0.52110 f 0.170333 0.173334 (0.230000) = 0.249337 Rx (0.230000) =- 1.46917e- 09f

Newton 插值程序.c