这是一个比较简单的程序,我是自己设计的,老师看过了,没有什么问题的,还得了一个优呢!-This is a relatively simple procedure, I was of their own design, the teacher looked at, there is no problem, but also a gifted it!
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.001227s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.090555s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.001491s ]
SELECT * FROM `jrk_tagrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 20 [ RunTime:0.001893s ]
SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.001687s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.005110s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.001027s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003890s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.014840s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.001064s ]
UPDATE `jrk_articles` SET `hits` = 2 WHERE `id` = 246669 [ RunTime:0.019192s ]