一种基本算法！ 现有一个酒店有100个房间，依次编号为1到100，第一个服务员经过，将所有房间门关上；第二个服务员经过将所有编号为2的倍数房门打开；第三个服务员...

一种基本算法！ 现有一个酒店有100个房间，依次编号为1到100，第一个服务员经过，将所有房间门关上；第二个服务员经过将所有编号为2的倍数房门打开；第三个服务员经过将所有编号为3倍数的房门打开的关上，关闭的打开。依此类推；输入一个100以内的正整数N，输出第N服务员经过之后，所有房间的状态。-a basic algorithm! An existing 100 hotel rooms, followed by No. 1-100, after an attendant, all rooms will be closed; Second attendants after all No. 2 in multiples door open; Third attendants after all No. 3 multiples of the open door is shut, Guan the opening closed. XII; The importation of a hundred within the positive integer N, N output after attendants, all rooms in the state.

TEST2
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